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88.2026=3.148r^2
We move all terms to the left:
88.2026-(3.148r^2)=0
We get rid of parentheses
-3.148r^2+88.2026=0
a = -3.148; b = 0; c = +88.2026;
Δ = b2-4ac
Δ = 02-4·(-3.148)·88.2026
Δ = 1110.6471392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1110.6471392}}{2*-3.148}=\frac{0-\sqrt{1110.6471392}}{-6.296} =-\frac{\sqrt{}}{-6.296} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1110.6471392}}{2*-3.148}=\frac{0+\sqrt{1110.6471392}}{-6.296} =\frac{\sqrt{}}{-6.296} $
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